If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(8x^2)-17x-68=0
a = 8; b = -17; c = -68;
Δ = b2-4ac
Δ = -172-4·8·(-68)
Δ = 2465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{2465}}{2*8}=\frac{17-\sqrt{2465}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{2465}}{2*8}=\frac{17+\sqrt{2465}}{16} $
| 5(5x+4)=46 | | 11x-3x+87=11x+57 | | 53(4x−5)=4x−13 | | 13=s/3–12 | | 60-y=261 | | 4x+8-4/2=46 | | 13j-1=(4j-7)/6 | | 3x-10(x=2)=13-7x | | 5^(x+1)+5^x=750 | | 2n=5×4 | | -n-3=2 | | 3x^2+441=432 | | (w+5)^2+3=47 | | 13j-1=4j-7/6 | | -8+-3w=-17 | | 4x-67=2x-13 | | X+6/8=3/4x | | 3x^2+49=432 | | 20x2-39x-80=0 | | -1/5xx=-4 | | 4(x-8)=10=-10 | | 4(3n+1)=9(6n+3)+1 | | 1/6(3t-5)=t+5/12 | | X^2-8x^2+24=0 | | 4*z+1/6=5z+7/6 | | 4+-c=14 | | 3(x+7)^2-(432)=0 | | 5v+2=-2v+9=7 | | 5n+34=-2=14 | | 4(4x+1)=3x-4(6-x)=8 | | 4x+9x-8x=19+1 | | (3x+10)-5x=6x+50 |